subkultures.net
main

create account

help

login
Well, it wasn't a dream and I didn't cuss
tetesuro
20040817 20:34:08 ET
Now, solve the following differential equation:
tx' = 4x + t^4
Hop to it friends!
Venadium
20040817 20:38:44 ET
x = why
Get it? Ha ha ha.
Courtney
20040817 20:48:14 ET
I hate math...algebra...whatever they're calling it these days.
Arsenic
20040818 01:44:02 ET
42
tetesuro
20040818 16:44:44 ET
x = t^4*ln(t)
x' = 4*t^3*ln(t)+t^3
First, I solve for x' by dividing the DE by t.
Then, I solve for the forceing function t^3
t^3 = x'  (4/t)*x
Then, I find the integrating factor u(t) = e^(int(4/t))
etc...
Return to tetesuro's page
TERMS OF SERVICE / PRIVACY POLICY
Everything on this page is copyrighted to the individual page owners and/or subkultures.net.