Well, it wasn't a dream and I didn't cuss

tetesuro 2004-08-17 20:34:08 ET Now, solve the following differential equation: tx' = 4x + t^4 Hop to it friends!

Venadium 2004-08-17 20:38:44 ET x = why Get it? Ha ha ha.

Courtney 2004-08-17 20:48:14 ET I hate math...algebra...whatever they're calling it these days.

Arsenic 2004-08-18 01:44:02 ET 42

tetesuro 2004-08-18 16:44:44 ET x = t^4*ln(t) x' = 4*t^3*ln(|t|)+t^3 First, I solve for x' by dividing the DE by t. Then, I solve for the forceing function t^3 t^3 = x' - (4/t)*x Then, I find the integrating factor u(t) = e^(int(4/t)) etc...

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