Well, it wasn't a dream and I didn't cuss
2004-08-17 20:34:08 ET
Now, solve the following differential equation:
tx' = 4x + t^4
Hop to it friends!
2004-08-17 20:38:44 ET
x = why
Get it? Ha ha ha.
2004-08-17 20:48:14 ET
I hate math...algebra...whatever they're calling it these days.
2004-08-18 01:44:02 ET
2004-08-18 16:44:44 ET
x = t^4*ln(t)
x' = 4*t^3*ln(|t|)+t^3
First, I solve for x' by dividing the DE by t.
Then, I solve for the forceing function t^3
t^3 = x' - (4/t)*x
Then, I find the integrating factor u(t) = e^(int(4/t))
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